20/4a-1=4/2a

Solution for 20/4a-1=4/2a equation:

20/4a-1=4/2a

We move all terms to the left:

20/4a-1-(4/2a)=0


Domain of the equation: 4a!=0

a!=0/4

a!=0

a∈R



Domain of the equation: 2a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

20/4a-(+4/2a)-1=0

We get rid of parentheses

20/4a-4/2a-1=0

We calculate fractions


40a/8a^2+(-16a)/8a^2-1=0

We multiply all the terms by the denominator


40a+(-16a)-1*8a^2=0

Wy multiply elements

-8a^2+40a+(-16a)=0

We get rid of parentheses

-8a^2+40a-16a=0

We add all the numbers together, and all the variables

-8a^2+24a=0

a = -8; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-8)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-8}=\frac{-48}{-16}
=+3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-8}=\frac{0}{-16}
=0
$