20/4x-3=5/x

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Solution for 20/4x-3=5/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(20/4)*x-3 = 5/x // - 5/x

(20/4)*x-(5/x)-3 = 0

(20/4)*x-5*x^-1-3 = 0

5*x^1-5*x^-1-3*x^0 = 0

(5*x^2-3*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-3*x^1-5*x^0) = 0

x^1

5*x^2-3*x-5 = 0

5*x^2-3*x-5 = 0

DELTA = (-3)^2-(-5*4*5)

DELTA = 109

DELTA > 0

x = (109^(1/2)+3)/(2*5) or x = (3-109^(1/2))/(2*5)

x = (109^(1/2)+3)/10 or x = (3-109^(1/2))/10

x in { (3-109^(1/2))/10, (109^(1/2)+3)/10}

x in { (3-109^(1/2))/10, (109^(1/2)+3)/10 }

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