20/n+5=9n=

Solution for 20/n+5=9n= equation:

20/n+5=9n=

We move all terms to the left:

20/n+5-(9n)=0


Domain of the equation: n!=0

n∈R


We add all the numbers together, and all the variables

-9n+20/n+5=0

We multiply all the terms by the denominator


-9n*n+5*n+20=0

We add all the numbers together, and all the variables

5n-9n*n+20=0

Wy multiply elements

-9n^2+5n+20=0

a = -9; b = 5; c = +20;
Δ = b2-4ac
Δ = 52-4·(-9)·20
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{745}}{2*-9}=\frac{-5-\sqrt{745}}{-18}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{745}}{2*-9}=\frac{-5+\sqrt{745}}{-18}
$