20/n-20/(n-2)=4/n

Solution for 20/n-20/(n-2)=4/n equation:

20/n-20/(n-2)=4/n

We move all terms to the left:

20/n-20/(n-2)-(4/n)=0


Domain of the equation: n!=0

n∈R



Domain of the equation: (n-2)!=0

We move all terms containing n to the left, all other terms to the right

n!=2

n∈R



Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

20/n-20/(n-2)-(+4/n)=0

We get rid of parentheses

20/n-20/(n-2)-4/n=0

We calculate fractions


(-4n+28)/(n^2-2n)+(-20n)/(n^2-2n)=0

We multiply all the terms by the denominator


(-4n+28)+(-20n)=0

We get rid of parentheses

-4n-20n+28=0

We add all the numbers together, and all the variables

-24n+28=0

We move all terms containing n to the left, all other terms to the right

-24n=-28

n=-28/-24

n=1+1/6