20/p+100=-10/2p

Solution for 20/p+100=-10/2p equation:

D( p )

p = 0

p = 0

p = 0

p in (-oo:0) U (0:+oo)

20/p+100 = (-10/2)*p // - (-10/2)*p

20/p-((-10/2)*p)+100 = 0

5*p+20/p+100 = 0

5*p^1+20*p^-1+100*p^0 = 0

(5*p^2+100*p^1+20*p^0)/(p^1) = 0 // * p^2

p^1*(5*p^2+100*p^1+20*p^0) = 0

p^1

5*p^2+100*p+20 = 0

5*p^2+100*p+20 = 0

DELTA = 100^2-(4*5*20)

DELTA = 9600

DELTA > 0

p = (9600^(1/2)-100)/(2*5) or p = (-9600^(1/2)-100)/(2*5)

p = (40*6^(1/2)-100)/10 or p = (-40*6^(1/2)-100)/10

p in { (-40*6^(1/2)-100)/10, (40*6^(1/2)-100)/10} 

p in { (-40*6^(1/2)-100)/10, (40*6^(1/2)-100)/10 }