200(x-5)=100(x+1)+500

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Solution for 200(x-5)=100(x+1)+500 equation: 



200(x-5)=100(x+1)+500

We move all terms to the left:

200(x-5)-(100(x+1)+500)=0

We multiply parentheses

200x-(100(x+1)+500)-1000=0



We calculate terms in parentheses: -(100(x+1)+500), so:

100(x+1)+500

We multiply parentheses

100x+100+500

We add all the numbers together, and all the variables

100x+600

Back to the equation:

-(100x+600)



We get rid of parentheses

200x-100x-600-1000=0

We add all the numbers together, and all the variables

100x-1600=0

We move all terms containing x to the left, all other terms to the right

100x=1600

x=1600/100

x=16

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