200+3/2x=548-7/5x

Solution for 200+3/2x=548-7/5x equation:

200+3/2x=548-7/5x

We move all terms to the left:

200+3/2x-(548-7/5x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x-(-7/5x+548)+200=0

We get rid of parentheses

3/2x+7/5x-548+200=0

We calculate fractions


15x/10x^2+14x/10x^2-548+200=0

We add all the numbers together, and all the variables

15x/10x^2+14x/10x^2-348=0

We multiply all the terms by the denominator


15x+14x-348*10x^2=0

We add all the numbers together, and all the variables

29x-348*10x^2=0

Wy multiply elements

-3480x^2+29x=0

a = -3480; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-3480)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-3480}=\frac{-58}{-6960}
=1/120
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-3480}=\frac{0}{-6960}
=0
$