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200-(40/2)y=140+(100/10)y
We move all terms to the left:
200-(40/2)y-(140+(100/10)y)=0
Domain of the equation: 2)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 10)y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-20y-(140+10y)+200=0
We get rid of parentheses
-20y-10y-140+200=0
We add all the numbers together, and all the variables
-30y+60=0
We move all terms containing y to the left, all other terms to the right
-30y=-60
y=-60/-30
y=+2
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