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200-11/2x=548-12/5x
We move all terms to the left:
200-11/2x-(548-12/5x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-11/2x-(-12/5x+548)+200=0
We get rid of parentheses
-11/2x+12/5x-548+200=0
We calculate fractions
(-55x)/10x^2+24x/10x^2-548+200=0
We add all the numbers together, and all the variables
(-55x)/10x^2+24x/10x^2-348=0
We multiply all the terms by the denominator
(-55x)+24x-348*10x^2=0
We add all the numbers together, and all the variables
24x+(-55x)-348*10x^2=0
Wy multiply elements
-3480x^2+24x+(-55x)=0
We get rid of parentheses
-3480x^2+24x-55x=0
We add all the numbers together, and all the variables
-3480x^2-31x=0
a = -3480; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·(-3480)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*-3480}=\frac{0}{-6960} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*-3480}=\frac{62}{-6960} =-31/3480 $
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