2000+(400*n)=2800+(325*n)

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Solution for 2000+(400*n)=2800+(325*n) equation: 



2000+(400*n)=2800+(325*n)

We move all terms to the left:

2000+(400*n)-(2800+(325*n))=0

We add all the numbers together, and all the variables

(+400n)-(2800+(+325n))+2000=0

We get rid of parentheses

400n-(2800+(+325n))+2000=0



We calculate terms in parentheses: -(2800+(+325n)), so:

2800+(+325n)

determiningTheFunctionDomain
(+325n)+2800

We get rid of parentheses

325n+2800

Back to the equation:

-(325n+2800)



We get rid of parentheses

400n-325n-2800+2000=0

We add all the numbers together, and all the variables

75n-800=0

We move all terms containing n to the left, all other terms to the right

75n=800

n=800/75

n=10+2/3

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