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2000=x(150-3x)
We move all terms to the left:
2000-(x(150-3x))=0
We add all the numbers together, and all the variables
-(x(-3x+150))+2000=0
We calculate terms in parentheses: -(x(-3x+150)), so:We get rid of parentheses
x(-3x+150)
We multiply parentheses
-3x^2+150x
Back to the equation:
-(-3x^2+150x)
3x^2-150x+2000=0
a = 3; b = -150; c = +2000;
Δ = b2-4ac
Δ = -1502-4·3·2000
Δ = -1500
Delta is less than zero, so there is no solution for the equation
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