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2000x(x-0.03)=6000
We move all terms to the left:
2000x(x-0.03)-(6000)=0
We multiply parentheses
2000x^2-60x-6000=0
a = 2000; b = -60; c = -6000;
Δ = b2-4ac
Δ = -602-4·2000·(-6000)
Δ = 48003600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48003600}=\sqrt{400*120009}=\sqrt{400}*\sqrt{120009}=20\sqrt{120009}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20\sqrt{120009}}{2*2000}=\frac{60-20\sqrt{120009}}{4000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20\sqrt{120009}}{2*2000}=\frac{60+20\sqrt{120009}}{4000} $
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