200=(20)(x)(2)

Solution for 200=(20)(x)(2) equation:

200=(20)(x)(2)

We move all terms to the left:

200-((20)(x)(2))=0

determiningTheFunctionDomain
-20x2+200=0

We add all the numbers together, and all the variables

-20x^2+200=0

a = -20; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-20)·200
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{10}}{2*-20}=\frac{0-40\sqrt{10}}{-40}
=-\frac{40\sqrt{10}}{-40}
=-\frac{\sqrt{10}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{10}}{2*-20}=\frac{0+40\sqrt{10}}{-40}
=\frac{40\sqrt{10}}{-40}
=\frac{\sqrt{10}}{-1}
$