200=(40+20x)/(1+.05x)

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Solution for 200=(40+20x)/(1+.05x) equation: 



200=(40+20x)/(1+.05x)

We move all terms to the left:

200-((40+20x)/(1+.05x))=0



Domain of the equation: (1+.05x))!=0

We move all terms containing x to the left, all other terms to the right

.05x)!=-1

x!=-1/1

x!=-1

x∈R



We add all the numbers together, and all the variables

-((20x+40)/(.05x+1))+200=0

We multiply all the terms by the denominator


-((20x+40)+200*(.05x+1))=0



We calculate terms in parentheses: -((20x+40)+200*(.05x+1)), so:

(20x+40)+200*(.05x+1)

We multiply parentheses

(20x+40)+200x+200

We get rid of parentheses

20x+200x+40+200

We add all the numbers together, and all the variables

220x+240

Back to the equation:

-(220x+240)



We get rid of parentheses

-220x-240=0

We move all terms containing x to the left, all other terms to the right

-220x=240

x=240/-220

x=-1+1/11

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