200=-16t2-12t+200

Solution for 200=-16t2-12t+200 equation:

200=-16t^2-12t+200

We move all terms to the left:

200-(-16t^2-12t+200)=0

We get rid of parentheses

16t^2+12t-200+200=0

We add all the numbers together, and all the variables

16t^2+12t=0

a = 16; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·16·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*16}=\frac{-24}{32}
=-3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*16}=\frac{0}{32}
=0
$