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200=80x^2
We move all terms to the left:
200-(80x^2)=0
a = -80; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-80)·200
Δ = 64000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{64000}=\sqrt{6400*10}=\sqrt{6400}*\sqrt{10}=80\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{10}}{2*-80}=\frac{0-80\sqrt{10}}{-160} =-\frac{80\sqrt{10}}{-160} =-\frac{\sqrt{10}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{10}}{2*-80}=\frac{0+80\sqrt{10}}{-160} =\frac{80\sqrt{10}}{-160} =\frac{\sqrt{10}}{-2} $
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