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200x-x2=9600
We move all terms to the left:
200x-x2-(9600)=0
We add all the numbers together, and all the variables
-1x^2+200x-9600=0
a = -1; b = 200; c = -9600;
Δ = b2-4ac
Δ = 2002-4·(-1)·(-9600)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-40}{2*-1}=\frac{-240}{-2} =+120 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+40}{2*-1}=\frac{-160}{-2} =+80 $
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