201/5(10x-20)=x-3

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Solution for 201/5(10x-20)=x-3 equation: 



201/5(10x-20)=x-3

We move all terms to the left:

201/5(10x-20)-(x-3)=0



Domain of the equation: 5(10x-20)!=0

x∈R



We get rid of parentheses

201/5(10x-20)-x+3=0

We multiply all the terms by the denominator


-x*5(10x-20)+3*5(10x-20)+201=0

Wy multiply elements

-5x^2(1+15x(1+201=0

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