202=2(4y+2)+2(5y)

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Solution for 202=2(4y+2)+2(5y) equation: 



202=2(4y+2)+2(5y)

We move all terms to the left:

202-(2(4y+2)+2(5y))=0



We calculate terms in parentheses: -(2(4y+2)+25y), so:

2(4y+2)+25y

We add all the numbers together, and all the variables

25y+2(4y+2)

We multiply parentheses

25y+8y+4

We add all the numbers together, and all the variables

33y+4

Back to the equation:

-(33y+4)



We get rid of parentheses

-33y-4+202=0

We add all the numbers together, and all the variables

-33y+198=0

We move all terms containing y to the left, all other terms to the right

-33y=-198

y=-198/-33

y=+6

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