208=2(10+2x)+(2x)

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Solution for 208=2(10+2x)+(2x) equation: 



208=2(10+2x)+(2x)

We move all terms to the left:

208-(2(10+2x)+(2x))=0

We add all the numbers together, and all the variables

-(2(2x+10)+2x)+208=0



We calculate terms in parentheses: -(2(2x+10)+2x), so:

2(2x+10)+2x

We add all the numbers together, and all the variables

2x+2(2x+10)

We multiply parentheses

2x+4x+20

We add all the numbers together, and all the variables

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

-6x-20+208=0

We add all the numbers together, and all the variables

-6x+188=0

We move all terms containing x to the left, all other terms to the right

-6x=-188

x=-188/-6

x=31+1/3

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