20=(13-3x)/2

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Solution for 20=(13-3x)/2 equation: 



20=(13-3x)/2

We move all terms to the left:

20-((13-3x)/2)=0

We add all the numbers together, and all the variables

-((-3x+13)/2)+20=0

We multiply all the terms by the denominator


-((-3x+13)+20*2)=0



We calculate terms in parentheses: -((-3x+13)+20*2), so:

(-3x+13)+20*2

We add all the numbers together, and all the variables

(-3x+13)+40

We get rid of parentheses

-3x+13+40

We add all the numbers together, and all the variables

-3x+53

Back to the equation:

-(-3x+53)



We get rid of parentheses

3x-53=0

We move all terms containing x to the left, all other terms to the right

3x=53

x=53/3

x=17+2/3

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