20=(2x-4)*2

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Solution for 20=(2x-4)*2 equation: 



20=(2x-4)*2

We move all terms to the left:

20-((2x-4)*2)=0



We calculate terms in parentheses: -((2x-4)*2), so:

(2x-4)*2

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

-4x+8+20=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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