20=(3+n)

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Solution for 20=(3+n) equation: 



20=(3+n)

We move all terms to the left:

20-((3+n))=0

We add all the numbers together, and all the variables

-((n+3))+20=0



We calculate terms in parentheses: -((n+3)), so:

(n+3)

We get rid of parentheses

n+3

Back to the equation:

-(n+3)



We get rid of parentheses

-n-3+20=0

We add all the numbers together, and all the variables

-1n+17=0

We move all terms containing n to the left, all other terms to the right

-n=-17

n=-17/-1

n=+17

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