20=(3/4)x-4

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Solution for 20=(3/4)x-4 equation: 



20=(3/4)x-4

We move all terms to the left:

20-((3/4)x-4)=0



Domain of the equation: 4)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3/4)x-4)+20=0

We multiply all the terms by the denominator


-((+3+20*4)x-4)=0



We calculate terms in parentheses: -((+3+20*4)x-4), so:

(+3+20*4)x-4

We add all the numbers together, and all the variables

83x-4

Back to the equation:

-(83x-4)



We get rid of parentheses

-83x+4=0

We move all terms containing x to the left, all other terms to the right

-83x=-4

x=-4/-83

x=4/83

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