20=(5/10c)

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Solution for 20=(5/10c) equation: 



20=(5/10c)

We move all terms to the left:

20-((5/10c))=0



Domain of the equation: 10c))!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+5/10c))+20=0

We multiply all the terms by the denominator


-((+5+20*10c))=0



We calculate terms in parentheses: -((+5+20*10c)), so:

(+5+20*10c)

We add all the numbers together, and all the variables

(20*10c+5)

We get rid of parentheses

20*10c+5

Wy multiply elements

200c+5

Back to the equation:

-(200c+5)



We get rid of parentheses

-200c-5=0

We move all terms containing c to the left, all other terms to the right

-200c=5

c=5/-200

c=-1/40

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