20=(b)(b+4)/2

Solution for 20=(b)(b+4)/2 equation:

20=(b)(b+4)/2

We move all terms to the left:

20-((b)(b+4)/2)=0

We multiply all the terms by the denominator


-(b(b+4)+20*2)=0


We calculate terms in parentheses: -(b(b+4)+20*2), so:

b(b+4)+20*2

We add all the numbers together, and all the variables

b(b+4)+40

We multiply parentheses

b^2+4b+40

Back to the equation:

-(b^2+4b+40)


We get rid of parentheses

-b^2-4b-40=0

We add all the numbers together, and all the variables

-1b^2-4b-40=0

a = -1; b = -4; c = -40;
Δ = b2-4ac
Δ = -42-4·(-1)·(-40)
Δ = -144
Delta is less than zero, so there is no solution for the equation