20=+3(12+4x)

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Solution for 20=+3(12+4x) equation: 



20=+3(12+4x)

We move all terms to the left:

20-(+3(12+4x))=0

We add all the numbers together, and all the variables

-(+3(4x+12))+20=0



We calculate terms in parentheses: -(+3(4x+12)), so:

+3(4x+12)

determiningTheFunctionDomain
3(4x+12)

We multiply parentheses

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

-12x-36+20=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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