20=-4(3x+3)+13x

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Solution for 20=-4(3x+3)+13x equation: 



20=-4(3x+3)+13x

We move all terms to the left:

20-(-4(3x+3)+13x)=0



We calculate terms in parentheses: -(-4(3x+3)+13x), so:

-4(3x+3)+13x

We add all the numbers together, and all the variables

13x-4(3x+3)

We multiply parentheses

13x-12x-12

We add all the numbers together, and all the variables

x-12

Back to the equation:

-(x-12)



We get rid of parentheses

-x+12+20=0

We add all the numbers together, and all the variables

-1x+32=0

We move all terms containing x to the left, all other terms to the right

-x=-32

x=-32/-1

x=+32

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