20=-4+3(a-11)=23

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Solution for 20=-4+3(a-11)=23 equation: 



20=-4+3(a-11)=23

We move all terms to the left:

20-(-4+3(a-11))=0



We calculate terms in parentheses: -(-4+3(a-11)), so:

-4+3(a-11)

determiningTheFunctionDomain
3(a-11)-4

We multiply parentheses

3a-33-4

We add all the numbers together, and all the variables

3a-37

Back to the equation:

-(3a-37)



We get rid of parentheses

-3a+37+20=0

We add all the numbers together, and all the variables

-3a+57=0

We move all terms containing a to the left, all other terms to the right

-3a=-57

a=-57/-3

a=+19

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