20=-6(4x+1)+2(-5+3x)

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Solution for 20=-6(4x+1)+2(-5+3x) equation: 



20=-6(4x+1)+2(-5+3x)

We move all terms to the left:

20-(-6(4x+1)+2(-5+3x))=0

We add all the numbers together, and all the variables

-(-6(4x+1)+2(3x-5))+20=0



We calculate terms in parentheses: -(-6(4x+1)+2(3x-5)), so:

-6(4x+1)+2(3x-5)

We multiply parentheses

-24x+6x-6-10

We add all the numbers together, and all the variables

-18x-16

Back to the equation:

-(-18x-16)



We get rid of parentheses

18x+16+20=0

We add all the numbers together, and all the variables

18x+36=0

We move all terms containing x to the left, all other terms to the right

18x=-36

x=-36/18

x=-2

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