20=-8(x+2)-4

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Solution for 20=-8(x+2)-4 equation: 



20=-8(x+2)-4

We move all terms to the left:

20-(-8(x+2)-4)=0



We calculate terms in parentheses: -(-8(x+2)-4), so:

-8(x+2)-4

We multiply parentheses

-8x-16-4

We add all the numbers together, and all the variables

-8x-20

Back to the equation:

-(-8x-20)



We get rid of parentheses

8x+20+20=0

We add all the numbers together, and all the variables

8x+40=0

We move all terms containing x to the left, all other terms to the right

8x=-40

x=-40/8

x=-5

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