20=-8y+2(y-2)

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Solution for 20=-8y+2(y-2) equation: 



20=-8y+2(y-2)

We move all terms to the left:

20-(-8y+2(y-2))=0



We calculate terms in parentheses: -(-8y+2(y-2)), so:

-8y+2(y-2)

We multiply parentheses

-8y+2y-4

We add all the numbers together, and all the variables

-6y-4

Back to the equation:

-(-6y-4)



We get rid of parentheses

6y+4+20=0

We add all the numbers together, and all the variables

6y+24=0

We move all terms containing y to the left, all other terms to the right

6y=-24

y=-24/6

y=-4

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