20=1/2n(n-3)

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Solution for 20=1/2n(n-3) equation: 



20=1/2n(n-3)

We move all terms to the left:

20-(1/2n(n-3))=0



Domain of the equation: 2n(n-3))!=0

n∈R



We multiply all the terms by the denominator


-(1+20*2n(n-3))=0



We calculate terms in parentheses: -(1+20*2n(n-3)), so:

1+20*2n(n-3)

determiningTheFunctionDomain
20*2n(n-3)+1

Wy multiply elements

40n(n+1

Back to the equation:

-(40n(n+1)





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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