20=10-3(12+4x)

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Solution for 20=10-3(12+4x) equation: 



20=10-3(12+4x)

We move all terms to the left:

20-(10-3(12+4x))=0

We add all the numbers together, and all the variables

-(10-3(4x+12))+20=0



We calculate terms in parentheses: -(10-3(4x+12)), so:

10-3(4x+12)

determiningTheFunctionDomain
-3(4x+12)+10

We multiply parentheses

-12x-36+10

We add all the numbers together, and all the variables

-12x-26

Back to the equation:

-(-12x-26)



We get rid of parentheses

12x+26+20=0

We add all the numbers together, and all the variables

12x+46=0

We move all terms containing x to the left, all other terms to the right

12x=-46

x=-46/12

x=-3+5/6

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