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20=14-2(5a+2)a=
We move all terms to the left:
20-(14-2(5a+2)a)=0
We calculate terms in parentheses: -(14-2(5a+2)a), so:We get rid of parentheses
14-2(5a+2)a
determiningTheFunctionDomain -2(5a+2)a+14
We multiply parentheses
-10a^2-4a+14
Back to the equation:
-(-10a^2-4a+14)
10a^2+4a-14+20=0
We add all the numbers together, and all the variables
10a^2+4a+6=0
a = 10; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·10·6
Δ = -224
Delta is less than zero, so there is no solution for the equation
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