20=2(j+4)

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Solution for 20=2(j+4) equation:



20=2(j+4)
We move all terms to the left:
20-(2(j+4))=0
We calculate terms in parentheses: -(2(j+4)), so:
2(j+4)
We multiply parentheses
2j+8
Back to the equation:
-(2j+8)
We get rid of parentheses
-2j-8+20=0
We add all the numbers together, and all the variables
-2j+12=0
We move all terms containing j to the left, all other terms to the right
-2j=-12
j=-12/-2
j=+6

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