20=2(r+3)

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Solution for 20=2(r+3) equation:



20=2(r+3)
We move all terms to the left:
20-(2(r+3))=0
We calculate terms in parentheses: -(2(r+3)), so:
2(r+3)
We multiply parentheses
2r+6
Back to the equation:
-(2r+6)
We get rid of parentheses
-2r-6+20=0
We add all the numbers together, and all the variables
-2r+14=0
We move all terms containing r to the left, all other terms to the right
-2r=-14
r=-14/-2
r=+7

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