20=2(u+3)+6

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Solution for 20=2(u+3)+6 equation: 



20=2(u+3)+6

We move all terms to the left:

20-(2(u+3)+6)=0



We calculate terms in parentheses: -(2(u+3)+6), so:

2(u+3)+6

We multiply parentheses

2u+6+6

We add all the numbers together, and all the variables

2u+12

Back to the equation:

-(2u+12)



We get rid of parentheses

-2u-12+20=0

We add all the numbers together, and all the variables

-2u+8=0

We move all terms containing u to the left, all other terms to the right

-2u=-8

u=-8/-2

u=+4

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