20=2(u+4)+2u

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Solution for 20=2(u+4)+2u equation: 



20=2(u+4)+2u

We move all terms to the left:

20-(2(u+4)+2u)=0



We calculate terms in parentheses: -(2(u+4)+2u), so:

2(u+4)+2u

We add all the numbers together, and all the variables

2u+2(u+4)

We multiply parentheses

2u+2u+8

We add all the numbers together, and all the variables

4u+8

Back to the equation:

-(4u+8)



We get rid of parentheses

-4u-8+20=0

We add all the numbers together, and all the variables

-4u+12=0

We move all terms containing u to the left, all other terms to the right

-4u=-12

u=-12/-4

u=+3

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