20=2(z+5)

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Solution for 20=2(z+5) equation:



20=2(z+5)
We move all terms to the left:
20-(2(z+5))=0
We calculate terms in parentheses: -(2(z+5)), so:
2(z+5)
We multiply parentheses
2z+10
Back to the equation:
-(2z+10)
We get rid of parentheses
-2z-10+20=0
We add all the numbers together, and all the variables
-2z+10=0
We move all terms containing z to the left, all other terms to the right
-2z=-10
z=-10/-2
z=+5

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