20=2(z+5)

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Solution for 20=2(z+5) equation: 



20=2(z+5)

We move all terms to the left:

20-(2(z+5))=0



We calculate terms in parentheses: -(2(z+5)), so:

2(z+5)

We multiply parentheses

2z+10

Back to the equation:

-(2z+10)



We get rid of parentheses

-2z-10+20=0

We add all the numbers together, and all the variables

-2z+10=0

We move all terms containing z to the left, all other terms to the right

-2z=-10

z=-10/-2

z=+5

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