20=3(2x+1)+7x

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Solution for 20=3(2x+1)+7x equation: 



20=3(2x+1)+7x

We move all terms to the left:

20-(3(2x+1)+7x)=0



We calculate terms in parentheses: -(3(2x+1)+7x), so:

3(2x+1)+7x

We add all the numbers together, and all the variables

7x+3(2x+1)

We multiply parentheses

7x+6x+3

We add all the numbers together, and all the variables

13x+3

Back to the equation:

-(13x+3)



We get rid of parentheses

-13x-3+20=0

We add all the numbers together, and all the variables

-13x+17=0

We move all terms containing x to the left, all other terms to the right

-13x=-17

x=-17/-13

x=1+4/13

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