20=3(4-5f)-f

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Solution for 20=3(4-5f)-f equation: 



20=3(4-5f)-f

We move all terms to the left:

20-(3(4-5f)-f)=0

We add all the numbers together, and all the variables

-(3(-5f+4)-f)+20=0



We calculate terms in parentheses: -(3(-5f+4)-f), so:

3(-5f+4)-f

We add all the numbers together, and all the variables

-1f+3(-5f+4)

We multiply parentheses

-1f-15f+12

We add all the numbers together, and all the variables

-16f+12

Back to the equation:

-(-16f+12)



We get rid of parentheses

16f-12+20=0

We add all the numbers together, and all the variables

16f+8=0

We move all terms containing f to the left, all other terms to the right

16f=-8

f=-8/16

f=-1/2

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