20=3(b+3)+2

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Solution for 20=3(b+3)+2 equation: 


Simplifying
20 = 3(b + 3) + 2

Reorder the terms:
20 = 3(3 + b) + 2
20 = (3 * 3 + b * 3) + 2
20 = (9 + 3b) + 2

Reorder the terms:
20 = 9 + 2 + 3b

Combine like terms: 9 + 2 = 11
20 = 11 + 3b

Solving
20 = 11 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
20 + -3b = 11 + 3b + -3b

Combine like terms: 3b + -3b = 0
20 + -3b = 11 + 0
20 + -3b = 11

Add '-20' to each side of the equation.
20 + -20 + -3b = 11 + -20

Combine like terms: 20 + -20 = 0
0 + -3b = 11 + -20
-3b = 11 + -20

Combine like terms: 11 + -20 = -9
-3b = -9

Divide each side by '-3'.
b = 3

Simplifying
b = 3

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