20=3(n-10)+2

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Solution for 20=3(n-10)+2 equation: 



20=3(n-10)+2

We move all terms to the left:

20-(3(n-10)+2)=0



We calculate terms in parentheses: -(3(n-10)+2), so:

3(n-10)+2

We multiply parentheses

3n-30+2

We add all the numbers together, and all the variables

3n-28

Back to the equation:

-(3n-28)



We get rid of parentheses

-3n+28+20=0

We add all the numbers together, and all the variables

-3n+48=0

We move all terms containing n to the left, all other terms to the right

-3n=-48

n=-48/-3

n=+16

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