20=3(n-3)

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Solution for 20=3(n-3) equation: 



20=3(n-3)

We move all terms to the left:

20-(3(n-3))=0



We calculate terms in parentheses: -(3(n-3)), so:

3(n-3)

We multiply parentheses

3n-9

Back to the equation:

-(3n-9)



We get rid of parentheses

-3n+9+20=0

We add all the numbers together, and all the variables

-3n+29=0

We move all terms containing n to the left, all other terms to the right

-3n=-29

n=-29/-3

n=9+2/3

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