20=3(y+2)-5y

Solution for 20=3(y+2)-5y equation:

20=3(y+2)-5y

We move all terms to the left:

20-(3(y+2)-5y)=0


We calculate terms in parentheses: -(3(y+2)-5y), so:

3(y+2)-5y

We add all the numbers together, and all the variables

-5y+3(y+2)

We multiply parentheses

-5y+3y+6

We add all the numbers together, and all the variables

-2y+6

Back to the equation:

-(-2y+6)


We get rid of parentheses

2y-6+20=0

We add all the numbers together, and all the variables

2y+14=0

We move all terms containing y to the left, all other terms to the right

2y=-14

y=-14/2

y=-7