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20=30-5(x+1)
We move all terms to the left:
20-(30-5(x+1))=0
We calculate terms in parentheses: -(30-5(x+1)), so:We get rid of parentheses
30-5(x+1)
determiningTheFunctionDomain -5(x+1)+30
We multiply parentheses
-5x-5+30
We add all the numbers together, and all the variables
-5x+25
Back to the equation:
-(-5x+25)
5x-25+20=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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