20=4(4+u)

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Solution for 20=4(4+u) equation: 



20=4(4+u)

We move all terms to the left:

20-(4(4+u))=0

We add all the numbers together, and all the variables

-(4(u+4))+20=0



We calculate terms in parentheses: -(4(u+4)), so:

4(u+4)

We multiply parentheses

4u+16

Back to the equation:

-(4u+16)



We get rid of parentheses

-4u-16+20=0

We add all the numbers together, and all the variables

-4u+4=0

We move all terms containing u to the left, all other terms to the right

-4u=-4

u=-4/-4

u=1

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