20=4(4x+2)2-20

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Solution for 20=4(4x+2)2-20 equation: 



20=4(4x+2)2-20

We move all terms to the left:

20-(4(4x+2)2-20)=0



We calculate terms in parentheses: -(4(4x+2)2-20), so:

4(4x+2)2-20

We multiply parentheses

32x+16-20

We add all the numbers together, and all the variables

32x-4

Back to the equation:

-(32x-4)



We get rid of parentheses

-32x+4+20=0

We add all the numbers together, and all the variables

-32x+24=0

We move all terms containing x to the left, all other terms to the right

-32x=-24

x=-24/-32

x=3/4

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