20=4(d+2)

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Solution for 20=4(d+2) equation: 



20=4(d+2)

We move all terms to the left:

20-(4(d+2))=0



We calculate terms in parentheses: -(4(d+2)), so:

4(d+2)

We multiply parentheses

4d+8

Back to the equation:

-(4d+8)



We get rid of parentheses

-4d-8+20=0

We add all the numbers together, and all the variables

-4d+12=0

We move all terms containing d to the left, all other terms to the right

-4d=-12

d=-12/-4

d=+3

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